(4y^2-20y+25)(2y-5)=0

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Solution for (4y^2-20y+25)(2y-5)=0 equation: 


Simplifying
(4y2 + -20y + 25)(2y + -5) = 0

Reorder the terms:
(25 + -20y + 4y2)(2y + -5) = 0

Reorder the terms:
(25 + -20y + 4y2)(-5 + 2y) = 0

Multiply (25 + -20y + 4y2) * (-5 + 2y)
(25(-5 + 2y) + -20y * (-5 + 2y) + 4y2 * (-5 + 2y)) = 0
((-5 * 25 + 2y * 25) + -20y * (-5 + 2y) + 4y2 * (-5 + 2y)) = 0
((-125 + 50y) + -20y * (-5 + 2y) + 4y2 * (-5 + 2y)) = 0
(-125 + 50y + (-5 * -20y + 2y * -20y) + 4y2 * (-5 + 2y)) = 0
(-125 + 50y + (100y + -40y2) + 4y2 * (-5 + 2y)) = 0
(-125 + 50y + 100y + -40y2 + (-5 * 4y2 + 2y * 4y2)) = 0
(-125 + 50y + 100y + -40y2 + (-20y2 + 8y3)) = 0

Combine like terms: 50y + 100y = 150y
(-125 + 150y + -40y2 + -20y2 + 8y3) = 0

Combine like terms: -40y2 + -20y2 = -60y2
(-125 + 150y + -60y2 + 8y3) = 0

Solving
-125 + 150y + -60y2 + 8y3 = 0

Solving for variable 'y'.

The solution to this equation could not be determined.

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